(5x-2)/4=x^2

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Solution for (5x-2)/4=x^2 equation: 


x in (-oo:+oo)

(5*x-2)/4 = x^2 // - x^2

(5*x-2)/4-x^2 = 0

(5*x-2)/4+(4*(-x^2))/4 = 0

4*(-x^2)+5*x-2 = 0

5*x-4*x^2-2 = 0

5*x-4*x^2-2 = 0

5*x-4*x^2-2 = 0

DELTA = 5^2-(-4*(-2)*4)

DELTA = -7

DELTA < 0

1 = 0

1/4 = 0

1/4 = 0 // * 4

1 = 0

1 = 0

x belongs to the empty set

x belongs to the empty set

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